Swoop.. If you were on a bus/train that was in motion and you were stood in the aisle and then jumped in the air, why don't you land further back in the bus/train? Instead you seem to move forward with the vehicle and land in exactly the same spot.
Swoop.. If you were on a bus/train that was in motion and you were stood in the aisle and then jumped in the air, why don't you land further back in the bus/train? Instead you seem to move forward with the vehicle and land in exactly the same spot.
To the Regiment - I Wish I Was There
http://www.youtube.com/watch?v=ywEnImZ5VqE
he tries it from outside the train
wot a knobhead
Danbert...the only thing i can think of is the fact you are moving at the same speed as the train before you jump.
When you jump you will start off at the same velocity as the train, but then you will decelerate when you are in the air. The fact that you will only be in the air for a matter of a second, you will not move significantly as you will still be travelling at a similar velocity to the train.
see equation of motion:
s= ut + (at^2)/2
where s = distance, u = initial velocity t= time a = acceleration.
as t will be small, and "a" will be negative = s will be small.
Who cut your hair, Stevie Wonder?
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Why is this a question for Swoop?
Quote:
Originally Posted by Danbert
I'm now convinced that running into a headwind hurts you much more than a tailwind helps you.
Say you were running 7 miles at 7mph hour, 3½ miles out, 3½ miles back.
It would take you 60 minutes to complete your run.
Now suppose a wind was blowing which decreased your speed by 1mph on
the way out and increased your speed by 1mph on the way back.
The first 3½ miles (at 6mph) would take you 35 minutes.
The second 3½ miles (at 8mph) would take you 26¼ minutes (trust me).
Total time would be 61¼ minutes, so the wind has effectively added 1¼ minutes to your time.
So you were right Danbert!
Swoop knows all the answers. A bit like the Forums "Ask Elvis".
I've just decided I don't trust you anymore.
Clodhopper i've just realised that a=0 in my original equation, as there is no horizontal force.
If however, you performed this on the top of the train, the air resistance would provide a force towards the back of the train and you would land further back wouldn't you?
Who cut your hair, Stevie Wonder?